300

G.H2 Production

In Excel

LH2 Storage in Excel

This process can only be find on the Hydrogen spreadsheet, cell B62. This process defines a Share of feedstock input as feed( the rest as process fuel) value. We are going to handle this in a different way in the .net version but which is equivalent. Basically instead of having a part of the process fuel in Natural Gas and another part in Natural Gas : Feed loss as it is done in GREET Excel 1.8d.0, we are going to introduce a chemical reaction technology. The remaining NG which is coming from the feed and used as a process fuel will go through that Chemical Reaction Process, will produce 0 emissions, but will be accounted as a energy consumption.

In .net

XML

Here is the xml of that process :

<stationary id="300" name="G.H2 Production" notes="" urban_share="0.25;0;True;percentage">
    <group type="efficiency">
      <input source="previous" ref="59" amount="1055055852.62;0;True;energy" />
      <efficiency>
        <year value="0.68;0;True;percentage" year="1990" />
        <year value="0.69;0;True;percentage" year="1995" />
        <year value="0.71;0;True;percentage" year="2000" />
        <year value="0.715;0;True;percentage" year="2005" />
        <year value="0.715;0;True;percentage" year="2010" />
        <year value="0.72;0;True;percentage" year="2015" />
        <year value="0.73;0;True;percentage" year="2020" />
      </efficiency>
      <shares>
        <input share="0.998;0;True;percentage" purpose="stationary" mix="0" ref="59">
          <technology ref="110" share="0;0;True;percentage" />
          <technology ref="107" share="0;0;True;percentage" />
          <technology ref="114" share="0.597345919909995;0;True;percentage" />
          <technology ref="109" share="0;0;True;percentage" />
          <technology ref="120" share="0.402654080090005;0;True;percentage" />
        </input>
        <input share="0.002;0;True;percentage" purpose="stationary" mix="0" ref="73" />
      </shares>
    </group>
    <output ref="60" amount="1055055852.62;0;True;energy" />
  </stationary>

Assumptions

LH2 Production

We are trying to calculate some shares for the NG actually burned, and the NG lost in the chemical reaction.

The formula : $NG=10^{6}\cdot ({\frac {1}{eff}}-1)\cdot Share_{NG}$ is usually giving us the amount of NG process fuel used, here in that case a part of it will be used within the process without any combustion.

In Excel, the amount of process fuel is given by : $NG_{pf}=({\frac {10^{6}}{eff}}-(10^{6}({\frac {1}{eff}}-1)\cdot Share_{Electricity}))\cdot (1-FeedAsProcessFuel)$

And the amount of fuel used as feed is given by : $NG_{feed}=({\frac {10^{6}}{eff}}-(10^{6}({\frac {1}{eff}}-1)\cdot Share_{Electricity}))\cdot FeedAsProcessFuel)-10^{6}$

Moreover we know that $NG=NG_{pf}+NG_{feed}\,$ so from there we just have to find what are the shares of the $NG_{pf}\,$ and $NG_{feed}\,$, and assign one of them to a technology, the other to the chemical reaction.

Working on $NG_{pf}\,$ :
$NG_{pf}=({\frac {10^{6}}{eff}}-(10^{6}({\frac {1}{eff}}-1)\cdot Share_{Electricity}))\cdot (1-FeedAsProcessFuel)$

As $1=Share_{electricity}+Share_{NG}\,$

$NG_{pf}=10^{6}(\cdot ({\frac {1}{eff}}-1)\cdot Share_{NG}+1)\cdot (1-FeedAsProcessFuel)$

$NG_{pf}=(10^{6}\cdot ({\frac {1}{eff}}-1)\cdot Share_{NG}+10^{6})\cdot (1-FeedAsProcessFuel)$

$NG_{pf}=(10^{6}\cdot ({\frac {1}{eff}}-1)\cdot Share_{NG})\cdot (1+{\frac {10^{6}}{10^{6}\cdot ({\frac {1}{eff}}-1)\cdot Share_{NG}}})\cdot (1-FeedAsProcessFuel)$

$NG_{pf}=NG\cdot Share_{BoilerTechnology}$

where $Share_{BoilerTechnology}=(1+{\frac {10^{6}}{10^{6}\cdot ({\frac {1}{eff}}-1)\cdot Share_{NG}}})\cdot (1-FeedAsProcessFuel)$ This means that if the efficiency of the process is changed, out shares between the Chemical reaction and the NG Industrial Boiler has to be changed too. We don't want to have this anymore so we will just assign fixed numbers for the technology shares. For the NG process fuel it will be distributed among the Boiler and the SMR technologies, calculated with the 71.5% efficiency and 83% Share of feedstock input as feed, we got :

• $Share_{BoilerTechnology}=0.597345919909995\,$
• $Share_{SMRTechnology}=0.402654080090005\,$

Results

LH2 Storage in .net rev 3328

As we can see here, all the numbers without upstream are matching perfectly, but not for the SOx emissions. There might be an issue in the SOx balance for that process.